To Roxanne, the Hardworking Tutee!

Hi Roxanne, this post is dedicated to you!Im sure u will do well, just start bombarding yourself with too many questions!U GOTTTA RELAX!:D

1. Alfred and Benedict were given some $$ each. If Alfred spent $45 each and Benedict spent $90 each wee, A will still have $840 left when B spent all his $$. If A spent $90 each week, and B spend $45 each week, A would still have $210 left when B had spend all his $$.
a) How much $$did A receive?
b)How much $$did B receive?

I cant think of any pri sch way to solve it!Im so sorry! So, this is like the sec sch way for referencing, i think u gotta ask ur teacher:((

let first case no of days is X:
45X +840 = money A has.
90X= money B has.

Let second case no of days be Y:
210+90Y=money A has.
45Y=money B has.

Total $$ that A has and $$ that B has do not change,
therefore
45X+840=210+90Y---------------EQN1
45Y=90Y---------------------------EQN2

Then some working that i dun think u will understand cuz its secondary school stuff.....
A has $1050.
B has $420.


There were a total of 7200 B and G at a funfair. After 3/4 of the B and 1/2 of the girls left the funfair, there were 120 more G that B remaining behind. How many B were there at the funfair first?try drawing the model!1u of the Girls= 1u of B +120
720-240=480
480/6=80
80x4=320


E and F and G took part in 100m race. When E crossed the finish line , he was ahead of F by 20m and ahead of G by 40. F and G continued to race to the finish line without changing their speed. How far was G from the finish line when F completed the race?

When E finish, F still left 20m.
When E finish, G still left 40m.
Since you dunno the time, let the time that E finish be Xm/min.
In the same time F's speed= (80/x) m/min.
In the same time G's speed was=(60/x) m/min.

20/ (60/x) = x/3min (amt of min travelled to complete 20m)

In this x/3 min, G finish (x/3) x (60/x)= 20m.

40m-20m=20m(ans)